Y=-4.9x^2+48x

Solution for Y=-4.9x^2+48x equation:

=-4.9Y^2+48Y

We move all terms to the left:

-(-4.9Y^2+48Y)=0

We get rid of parentheses

4.9Y^2-48Y=0

a = 4.9; b = -48; c = 0;
Δ = b2-4ac
Δ = -482-4·4.9·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-48}{2*4.9}=\frac{0}{9.8}
=0
$
$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+48}{2*4.9}=\frac{96}{9.8}
=9+4.3333333333333/5.4444444444445
$